![]() ![]() To six equal parts to explain the condition for P to be third minimum is, a/6Ī sin θ = 3 λ (third minimum) (6.149) Condition for P to be nthorderĭividing the slit into 2 n number of (even number of) equal parts The condition for P to be second minimum, a/4 sinθ = λ/2Ĭondition for P to be third order minimum The path difference δ between waves from these corresponding Now, the widthĬorresponding points on the slit which are separated by the same width a/4. Let us divide the slit AB into four equal parts. The same width (here a/2) called corresponding points as shown in Figureįrom different corresponding points meeting at point P and interfereĭestructively to make it first minimum. We have different points on the slit which are separated by Let us divide the slit AB into two half ’s AC and CB. To explain maximum, the slit is divided into odd number of parts. Show that destructive interference takes place at that point to make it Then, add their contributions at P with the proper path difference to We need to give the condition for the point P to be of various minima. Geometrically shadowed region, up to which the central maximum is spread due toĭiffraction as shown Figure 6.63. Other from different points of the slit and interfere at point P and other points to give the resultant The lines joining P to the different points on the slit can be treated as parallel Would like to find the intensity at any point P on the screen. A straight line through C perpendicular to the plane of slit meets The diffractedīeam falls on a screen kept at a distance. Normally on a single slit AB of width a as shown in Figure 6.63. In laboratory conditions, convex lenses are to.Light wave is from a source at infinity.For laboratory conditions, convex lenses need.Light wave is from a source at finite distance.Spherical or cylindrical wavefront undergoes.The differences between Fresnel and FraunhoferĪs Fraunhofer diffraction is easy to observe andĪnalyse, let us take it up for further discussions. Undergoes diffraction, the diffraction could be classified as Fresnel andįraunhofer diffractions. When the obstacle size is of the order of wavelength of light. But the diffraction in light is more pronounced The wavelength of sound wave is large and comparable to the ![]() Why sound waves get diffracted prominently by obstacles like doors, windows,īuildings etc. Of the obstacle is comparable to the wavelength of light. But, the diffraction is prominent only when the size Have studied in ray optics, which says light should travel in straight line inĪ medium without bending. This is a violation to the rectilinear propagation of light, we Is bending of waves around sharp edges into the geometrically shadowed Of all types of waves, be it sound wave, light wave, water wave etc. ![]()
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